document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=159052>Question 159052</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What values of x would make the following equation undefined?<BR>\n" );
document.write( "1/x + 1/x+3 =2\r<BR>\n" );
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document.write( "Any help is appreciated! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #117145 by </B><A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><B>KnightOwlTutor(293)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KnightOwlTutor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=117145\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/0 is an undefined term. Therefore, any values of x that would make the denominator 0 would make the equation undefined. Thus, 0 and -3 would be the answers 1/0 and 1/-3+3=1/0. </SPAN>\n" );
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