document.write( "Question 159029This question is from textbook Glencoe Algebra 1
\n" ); document.write( ": 6y+2/3 = c for y Can you please show me step by step formula for the variable specified \n" ); document.write( "
Algebra.Com's Answer #117127 by nerdybill(7384)\"\" \"About 
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6y+2/3 = c
\n" ); document.write( "Start by getting rid of all denominators.
\n" ); document.write( "Do this by multiplying both sides by 3.
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\n" ); document.write( "18y+2 = 3c
\n" ); document.write( "Now, subtract both sides by 2:
\n" ); document.write( "18y = 3c - 2
\n" ); document.write( "Divide both sides by 18:
\n" ); document.write( "y = (3c)/18 - 2/18
\n" ); document.write( "reducing:
\n" ); document.write( "y = c/6 - 1/9\r
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