document.write( "Question 159006: Hoe many pounds of hamburger that costs 1.60 per pound must be mixed with 70 pounds of hamburger that costs 2.10 per pound to make a mixture that costs 1.70 per pound. \n" ); document.write( "

Algebra.Com's Answer #117120 by midwood_trail(310) $\"\"$ $\"About$

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How many pounds of hamburger that costs 1.60 per pound must be mixed with 70 pounds of hamburger that costs 2.10 per pound to make a mixture that costs 1.70 per pound?\r
\n" ); document.write( "\n" ); document.write( "Here is the set up:\r
\n" ); document.write( "\n" ); document.write( "[first mixture] + [second mixture] = [total mixture]\r
\n" ); document.write( "\n" ); document.write( "[x(1.60)] + [2.10(70)] = [1.70(x + 70)]\r
\n" ); document.write( "\n" ); document.write( "We are looking for x.\r
\n" ); document.write( "\n" ); document.write( "x1.60 + 147 = 1.70x + 119\r
\n" ); document.write( "\n" ); document.write( "x1.60 - 1.70x = -147 + 119\r
\n" ); document.write( "\n" ); document.write( "-0.1x = -28\r
\n" ); document.write( "\n" ); document.write( "x = -28/-0.1\r
\n" ); document.write( "\n" ); document.write( "x = 280\r
\n" ); document.write( "\n" ); document.write( "How many pounds of hamburger that costs 1.60 per pound must be mixed?\r
\n" ); document.write( "\n" ); document.write( "The answer is 280 pounds.\r
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