document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=21806>Question 21806</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A square piece of paper is folded in half vertically. If the resulting figure has a perimeter of 12 cm, what was the area of the original square?\r<BR>\n" );
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document.write( "I got 48 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #11711 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=11711\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = original side of the square\r<BR>\n" );
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document.write( "Perimeter after folding = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+%2B+x+%2B+%281%2F2%29%2Ax+%2B+%281%2F2%29%2Ax+=+3x+=+12 ALIGN=MIDDLE  ALT=\"x+%2B+x+%2B+%281%2F2%29%2Ax+%2B+%281%2F2%29%2Ax+=+3x+=+12\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x=4\r<BR>\n" );
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document.write( "Area of the original square = L * W = 4*4 = 16 square centimeters.\r<BR>\n" );
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document.write( "R^2 at SCC </SPAN>\n" );
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