document.write( "Question 21807: Solve the system by the substitution method.
\n" ); document.write( "x + 5y = 5
\n" ); document.write( "3x - 8y = -8 \n" ); document.write( "
Algebra.Com's Answer #11710 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
First, solve for one of the variables in one of the equations. The easiest is to solve for x in the first equation:\r
\n" ); document.write( "\n" ); document.write( "x= 5-5y\r
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\n" ); document.write( "\n" ); document.write( "Substitute this back into the second equation in place of the x:
\n" ); document.write( "3x - 8y = -8
\n" ); document.write( "3(____) - 8y = -8
\n" ); document.write( "3(5-5y) - 8y = -8
\n" ); document.write( "15 - 15y - 8y = -8
\n" ); document.write( "15-23y = -8
\n" ); document.write( "15-15 -23y = -8-15
\n" ); document.write( "-23y = -23
\n" ); document.write( "y=1\r
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\n" ); document.write( "\n" ); document.write( "Now, substitute y = 1 back into the EASIEST equation to find x, which would be the x= 5-5y equation
\n" ); document.write( "x=5-5y
\n" ); document.write( "x=5 -5*1
\n" ); document.write( "x=0\r
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\n" ); document.write( "\n" ); document.write( "Check in the OTHER equation (not the one you just used to find x!):
\n" ); document.write( "3x-8y=-8
\n" ); document.write( "3(0)-8(1)=-8
\n" ); document.write( "-8=-8 It checks!\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC \n" ); document.write( "
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