document.write( "Question 158957: Please help me solve this problem, it is from a worksheet:\r
\n" ); document.write( "\n" ); document.write( "the measure of angle b, the complement of angle a is 1/6th the measure of angle c, the supplement of angle a Find the measure of each angle \n" ); document.write( "
Algebra.Com's Answer #117095 by nerdybill(7384)\"\" \"About 
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the measure of angle b, the complement of angle a is 1/6th the measure of angle c, the supplement of angle a Find the measure of each angle
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\n" ); document.write( "The problem expects you to know that:
\n" ); document.write( "If two angles are complementary, the sum of their angles equals 90 deg.
\n" ); document.write( "If two angles are supplementary, the sum of their angles equals 180 deg.
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\n" ); document.write( "Let a = angle
\n" ); document.write( "then
\n" ); document.write( "90-a = complement of the angle (angle b)
\n" ); document.write( "180-a = supplement of the angle a (angle c)
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\n" ); document.write( "Then from: \"the measure of angle b, the complement of angle a is 1/6th the measure of angle c, the supplement of angle a\" we get our equation of:
\n" ); document.write( "90-a = (1/6)(180-a)
\n" ); document.write( "multiplying both sides by 6:
\n" ); document.write( "540-6a = 180-a
\n" ); document.write( "540 = 180+5a
\n" ); document.write( "360 = 5a
\n" ); document.write( "72 degrees = a (angle a)
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\n" ); document.write( "Angle b:
\n" ); document.write( "90-a = 90-72 = 18 degrees (angle b)
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\n" ); document.write( "Angle c\"
\n" ); document.write( "180-a = 180-72 = 108 degrees (angle c)
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