document.write( "Question 158852: Part of $13,750 is invested at 9% interest and the rest is invested at 8%. After on year, the accounts paid $1,185 in interest. How much was invested at the lower rate? \n" ); document.write( "
Algebra.Com's Answer #117061 by checkley77(12844) ![]() You can put this solution on YOUR website! .08x+.09(13,750-x)=1,185 \n" ); document.write( ".08x+1,237.50-.09x=1,185 \n" ); document.write( "-.01x=1,185-1,237.50 \n" ); document.write( "-.01x=-52.50 \n" ); document.write( "x=-52.50/-.01 \n" ); document.write( "x=$5,250 is the amount invested @ 8%. \n" ); document.write( "13,750-5,250=$8,500 invested @ 9%. \n" ); document.write( "Proof. \n" ); document.write( ".08*5,250+.09*8,500=1,185 \n" ); document.write( "420+765=1,185 \n" ); document.write( "1,185=1,185 \n" ); document.write( " |