document.write( "Question 158852: Part of $13,750 is invested at 9% interest and the rest is invested at 8%. After on year, the accounts paid $1,185 in interest. How much was invested at the lower rate? \n" ); document.write( "
Algebra.Com's Answer #117061 by checkley77(12844)\"\" \"About 
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.08x+.09(13,750-x)=1,185
\n" ); document.write( ".08x+1,237.50-.09x=1,185
\n" ); document.write( "-.01x=1,185-1,237.50
\n" ); document.write( "-.01x=-52.50
\n" ); document.write( "x=-52.50/-.01
\n" ); document.write( "x=$5,250 is the amount invested @ 8%.
\n" ); document.write( "13,750-5,250=$8,500 invested @ 9%.
\n" ); document.write( "Proof.
\n" ); document.write( ".08*5,250+.09*8,500=1,185
\n" ); document.write( "420+765=1,185
\n" ); document.write( "1,185=1,185
\n" ); document.write( "
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