document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=158931>Question 158931</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of three numbers is 254. the second is 3 times the first, and the third is 5 less than the second. find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #117057 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=117057\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> second=3f<BR>\n" );
document.write( "third=s-5<BR>\n" );
document.write( "f=first<BR>\n" );
document.write( "f+3f+(3f-5)=254<BR>\n" );
document.write( "7f-5=254<BR>\n" );
document.write( "7f=254+5<BR>\n" );
document.write( "7f=259<BR>\n" );
document.write( "f=259/7<BR>\n" );
document.write( "f=37 is the first number.<BR>\n" );
document.write( "s=3*37=111 is the second number.<BR>\n" );
document.write( "t=111-5=106 is the third number.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "37+111+106=254<BR>\n" );
document.write( "254=254 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );