document.write( "Question 158892: sir i have a problem on solving this equation.
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document.write( "i am trying to solve x and to simplify it.
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document.write( "question: logx 8=-3?
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document.write( "i convert it to exponential form x^-3=8
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document.write( "this are the formulas I've tried to solve it but I'm not sure if it is correct.
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document.write( "a). (x^-3)^3=(8)^3
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document.write( " x=8^3
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document.write( " x=512:answer
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document.write( "b). i change the negative exponent to positive and transpose it to 8
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document.write( " x=8^3
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document.write( " x=512:answer
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document.write( "c). i get the reciprocal of the exponent and change it to 1/3
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document.write( " it became x^1/3=8
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document.write( " then i do: (cube root of x)^3 = (8)^3
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document.write( " i cancel out cube root of x and it became
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document.write( " x=8^3
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document.write( " x=512:answer
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document.write( "please help me to figure out the answer of this problem because I'm about to go crazy.\r
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document.write( "for my last question..
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document.write( "is this formula i have given is correct??
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document.write( "i mean is there any possible way to solve it??,,\r
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document.write( "thank you sir in advance.. \n" );
document.write( "
Algebra.Com's Answer #117032 by scott8148(6628)![]() ![]() You can put this solution on YOUR website! there is an error in a) __ (x^-3)^3=x^-9 __ the exponents multiply\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "try (x^-3)^(-1/3)=8^(-1/3) __ x=8^(-1/3) __ x=1/2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |