document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=158854>Question 158854</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi.  I am confused about the correct order of operation for the following problem:\r<BR>\n" );
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document.write( "     \"Evaluate the expression <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%287-y%29%2F10x++ ALIGN=MIDDLE  ALT=\"+%287-y%29%2F10x++\"   DISABLED_style= \"max-width:90%; height:auto;\" > WHEN y = 1/7, x = 2/7\"\r<BR>\n" );
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document.write( "The given answer 10/49, but I argue it is 5/2.  Could you help?\r<BR>\n" );
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document.write( "Thank you <BR>\n" );
document.write( "(Please note that in the original problem, a fraction bar is not used and a division sign is.  Also, the \"10 times x\" above was originally written \"10x.\" Does this make a difference?)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #117011 by </B><A HREF=/tutors/aboutme.mpl?userid=ranjithraghuram><B>ranjithraghuram(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ranjithraghuram><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=117011\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> by substituting the values of x and y in the equation we get the expression\r<BR>\n" );
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document.write( "{7-(1/7) }          /          {10 . (2/7)}\r<BR>\n" );
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document.write( "numerator                       denominator\r<BR>\n" );
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document.write( "Taking the lcm for the numerator, we get (48/7).  \r<BR>\n" );
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document.write( "When it comes to the denominator, multiplying 10 with (2/7) gives 20/7\r<BR>\n" );
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document.write( "So the total expression is (48/7) / (20/7) = (48/7) * (7/20) = 48/20 = 12/5.\r<BR>\n" );
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document.write( "So the answer is 12/5 </SPAN>\n" );
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