document.write( "Question 158855: Karen is working in the chemistry lab and needs a solution that is 8% hydrochloric acid. She has two solutions that she can mix together to get the solution of the required strength. The first solution is 2% hydrochloric acid, and the other is 11% hydrochloric acid. How many kilograms of each solution should she mix to produce four kilograms of the required strength. \n" ); document.write( "
Algebra.Com's Answer #117007 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
Karen is working in the chemistry lab and needs a solution that is 8% hydrochloric acid. She has two solutions that she can mix together to get the solution of the required strength. The first solution is 2% hydrochloric acid, and the other is 11% hydrochloric acid. How many kilograms of each solution should she mix to produce four kilograms of the required strength.
\n" ); document.write( ".
\n" ); document.write( "Let x = amt of 2% hydrochloric acid
\n" ); document.write( "then
\n" ); document.write( "4-x = amt of 11% hydrochloric acid
\n" ); document.write( ".
\n" ); document.write( "\"amt of acid from 2%\" + \"amt of acid from 11%\" = \"amt of acid desired\"
\n" ); document.write( "translating the above into an equation from our variables:
\n" ); document.write( ".02x + .11(4-x) = .08(4)
\n" ); document.write( "Solving then:
\n" ); document.write( ".02x + .44 - .11x = 0.32
\n" ); document.write( ".44 - .09x = 0.32
\n" ); document.write( ".44 = .09x + 0.32
\n" ); document.write( "0.12 = .09x
\n" ); document.write( "1.33 kilograms = x (amount of 2% hydrochloric acid)
\n" ); document.write( ".
\n" ); document.write( "11% hydrochloric acid:
\n" ); document.write( "4-x = 4-1.33 = 2.67 kilograms (amount of 11% hydrochloric acid)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );