document.write( "Question 158680: a car radiator contains 10 liters of a 30 percent anti freeze solution how many liters would have to be replaced with pure antifreeze if the resulting is to contain 50 percent? \n" ); document.write( "
Algebra.Com's Answer #117006 by ankor@dixie-net.com(22740)\"\" \"About 
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a car radiator contains 10 liters of a 30 percent anti freeze solution how many liters would have to be replaced with pure antifreeze if the resulting is to contain 50 percent?
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\n" ); document.write( "Let x = amt to be replaced by pure antifreeze
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\n" ); document.write( ".30(10-x) + 1.0x = .50(10)
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\n" ); document.write( "3 - .3x + 1.0x = 5
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\n" ); document.write( "+.7x = 5 - 3
\n" ); document.write( "x = \"2%2F.7\"
\n" ); document.write( "x = 2.857 liters to be replaced
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\n" ); document.write( "Check:
\n" ); document.write( ".3(10-2.857) + 2.857 = .5(10)
\n" ); document.write( ".3(7.143) + 2.857 = 5
\n" ); document.write( "2.1429 + 2.857 = 4.9999 ~ 5 \n" ); document.write( "
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