document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=158857>Question 158857</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many gallons of a 80% antifreeze must be mixed with 70 gallons of 25% antifreeze to get a mixture of 70% antifreeze </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #117004 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=117004\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How many gallons of a 80% antifreeze must be mixed with 70 gallons of 25% antifreeze to get a mixture of 70% antifreeze<BR>\n" );
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document.write( "Let x = amount of 80% antifreeze added<BR>\n" );
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document.write( "\"amt of antifreeze added\" + \"amt in antifreeze in the 70 gals\" = \"amt of antifreeze in final solution\"<BR>\n" );
document.write( ".80x + .25(70) = .70(70+x)<BR>\n" );
document.write( ".80x + 17.5 = 49 + .70x<BR>\n" );
document.write( ".10x + 17.5 = 49<BR>\n" );
document.write( ".10x = 31.5<BR>\n" );
document.write( "x = 31.5/.10<BR>\n" );
document.write( "x = 315 gallons\r<BR>\n" );
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