document.write( "Question 158617: five times the complement of an angle less twice the angle's supplement is 40 degrees. find the measure of the supplement. \n" ); document.write( "

Algebra.Com's Answer #116975 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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five times the complement of an angle less twice the angle's supplement is 40 degrees. find the measure of the supplement.
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\n" ); document.write( "Let x = \"the angle\"
\n" ); document.write( "Then
\n" ); document.write( "(90-x) = the Complement of the angle
\n" ); document.write( "and
\n" ); document.write( "(180-x) = the Supplement of the angle
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\n" ); document.write( "Just write what it says:
\n" ); document.write( "5(90-x) - 2(180-x) = 40
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\n" ); document.write( "450 - 5x - 360 + 2x = 40; change the sign inside the bracket
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\n" ); document.write( "-5x + 2x + 90 = 40
\n" ); document.write( ":
\n" ); document.write( "-3x = 40 - 90
\n" ); document.write( ":
\n" ); document.write( "-3x = -50
\n" ); document.write( "x = $\"%28-50%29%2F%28-3%29\"$
\n" ); document.write( "x = +16 $\"2%2F3\"$ degrees
\n" ); document.write( ":
\n" ); document.write( "Find the supplement:
\n" ); document.write( "180 - 16 $\"2%2F3\"$ = 163 $\"1%2F3\"$ degrees
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\n" ); document.write( "You can check the solution in the original equation \n" ); document.write( "

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