document.write( "Question 158814: The sum of the squares of three consecutive even integers is 116. Find the integers...
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document.write( "This is what I have tried...
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document.write( "x + (x + 2)+ (x + 4)= 116
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document.write( "3x + 6 = 116
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document.write( " -6 - 6
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document.write( " 3x = 110
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document.write( "3x/3 110/3
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document.write( " x = 36.6666\r
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document.write( "This doesnt make sense. What am i doing wrong?\r
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Algebra.Com's Answer #116964 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! You are asked for the sum of the [squares] \n" ); document.write( "You need to pay more attention to what is given & asked for. \n" ); document.write( "x + (x + 2)+ (x + 4)= 116 [x^2+(x+2)^2+(x+4)^2=116] \n" ); document.write( "3x + 6 = 116 [x^2+x^2+4x+4+x^2+8x+16=116] \n" ); document.write( "-6 - 6 [3x^2+12x+20-116=0] \n" ); document.write( " [3x^2 +12x-96=0] \n" ); document.write( "3x = 110 [3(x^2+4x-32)=0] \n" ); document.write( "3x/3 110/3 3(x+8)(x-4)=0] \n" ); document.write( "x = 36.6666 [x-4=0] \n" ); document.write( " [x=4] \n" ); document.write( "Proof: \n" ); document.write( "4^2+6^2+8^2=116 \n" ); document.write( "16+36+64=116 \n" ); document.write( "116=116 \n" ); document.write( " |