document.write( "Question 158802: hi,can anyone help me on this one:
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document.write( " (-4,2) perpendicular to 2x+3y=-6
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document.write( "i know i have to change 2x+3y=-6 to slope:y=mx+b
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document.write( "yeah. \n" );
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Algebra.Com's Answer #116958 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 2x+3y=-6 \n" ); document.write( "First we need to put this equation in the line equation form Y=mX+b where m=slope & b=the y intercept. \n" ); document.write( "3y=-2x-6 \n" ); document.write( "y=-2x/3-6/3 \n" ); document.write( "y=-2x/3-2 here we have a slope(m)=-2/3. \n" ); document.write( "Any line perpendicular to this line has a slope=3/2 (the negative reciprical of the original slope). \n" ); document.write( "Now replace the x&y terms with the values(-4,2) & the new slope & solve for b. \n" ); document.write( "2=3/2*-4+b \n" ); document.write( "2=-12/2+b \n" ); document.write( "2=-6+b \n" ); document.write( "b=2=6 \n" ); document.write( "b=8 for the y intercept (0,8). \n" ); document.write( "y=3x/2+8 (green line) is this perpendicular line to y=-2x/3-2 (red line) & passes through (-4,2). \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |