document.write( "Question 158802: hi,can anyone help me on this one:
\n" ); document.write( " (-4,2) perpendicular to 2x+3y=-6
\n" ); document.write( "i know i have to change 2x+3y=-6 to slope:y=mx+b
\n" ); document.write( "yeah.
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Algebra.Com's Answer #116958 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
2x+3y=-6
\n" ); document.write( "First we need to put this equation in the line equation form Y=mX+b where m=slope & b=the y intercept.
\n" ); document.write( "3y=-2x-6
\n" ); document.write( "y=-2x/3-6/3
\n" ); document.write( "y=-2x/3-2 here we have a slope(m)=-2/3.
\n" ); document.write( "Any line perpendicular to this line has a slope=3/2 (the negative reciprical of the original slope).
\n" ); document.write( "Now replace the x&y terms with the values(-4,2) & the new slope & solve for b.
\n" ); document.write( "2=3/2*-4+b
\n" ); document.write( "2=-12/2+b
\n" ); document.write( "2=-6+b
\n" ); document.write( "b=2=6
\n" ); document.write( "b=8 for the y intercept (0,8).
\n" ); document.write( "y=3x/2+8 (green line) is this perpendicular line to y=-2x/3-2 (red line) & passes through (-4,2).
\n" ); document.write( "\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+-2x%2F3+-2%2C+3x%2F2+%2B8%29+\" (graph 300x300 pixels, x from -10 to 10, y from -10 to 10, of TWO functions -2x/3 -2 and 3x/2 +8).
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