document.write( "Question 158669: A photo is 3 inches longer that it is wide. A 2-inch border is placed around the photo making the total area of the photo and border 108in^2. What are the dimensions of the photo. \n" ); document.write( "
Algebra.Com's Answer #116912 by ankor@dixie-net.com(22740)\"\" \"About 
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A photo is 3 inches longer that it is wide. A 2-inch border is placed around the photo making the total area of the photo and border 108in^2. What are the dimensions of the photo.
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\n" ); document.write( "Let x = the width of the photo
\n" ); document.write( "based on the 1st sentence we can say:
\n" ); document.write( "(x+3) = the length of the photo
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\n" ); document.write( "With a 2\" border the overall dimensions would be (x+3) + 4, by x + 4
\n" ); document.write( "which is (x+7) by (x+4)
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\n" ); document.write( "The overall area is given, therefore:
\n" ); document.write( "(x+7)*(x+4) = 108
\n" ); document.write( "FOIL
\n" ); document.write( "x^2 + 4x + 7x + 28 = 108
\n" ); document.write( "Arrange as a quadratic equation
\n" ); document.write( "x^2 + 11x + 28 - 108 = 0
\n" ); document.write( "x^2 + 11x - 80 = 0
\n" ); document.write( "Factors to:
\n" ); document.write( "(x+16)(x-5) = 0
\n" ); document.write( "Positive solution
\n" ); document.write( "x = +5\" is the width of the photo
\n" ); document.write( "and
\n" ); document.write( "5+3 = 8\" is the length of the photo
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\n" ); document.write( "Check the solution by finding the overall area; 12 * 9 = 108 \n" ); document.write( "
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