document.write( "Question 158668This question is from textbook Prentice hall mathmatics
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document.write( ": It takes 1 hour longer to fly to St. Paul at 200 mi/h than it does to return at 250 mi/h. How far away is St. Paul? \n" );
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Algebra.Com's Answer #116905 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! It takes 1 hour longer to fly to St. Paul at 200 mi/h than it does to return at 250 mi/h. \n" ); document.write( " How far away is St. Paul? \n" ); document.write( ": \n" ); document.write( "Find the time first: \n" ); document.write( ": \n" ); document.write( "Let t = time required to fly to St.P \n" ); document.write( "then \n" ); document.write( "(t-1) = time to return \n" ); document.write( ": \n" ); document.write( "The distance to and from are equal; write a distance equation: Dist = speed*time \n" ); document.write( ": \n" ); document.write( "To dist = return dist \n" ); document.write( ": \n" ); document.write( "200t = 250(t-1) \n" ); document.write( "200t = 250t - 250 \n" ); document.write( "+250 = 250t - 200t \n" ); document.write( "t = \n" ); document.write( "t = 5 hrs to make the trip \n" ); document.write( "and \n" ); document.write( "5 - 1 = 4 hrs to make the return trip \n" ); document.write( "; \n" ); document.write( "Find the dist: \n" ); document.write( "200 * 5 = 1000 mi \n" ); document.write( "or \n" ); document.write( "250 * 4 = 1000 mis \n" ); document.write( " |