document.write( "Question 158692This question is from textbook beginning and intermidiate algebra
\n" ); document.write( ": on average, a canada goose can fly 10 mph faster than a great blue heron. find their flying speeds if a goose can fly 120 miles in the same time it takes a heron to fly 80 miles \n" ); document.write( "
Algebra.Com's Answer #116882 by jojo14344(1513)\"\" \"About 
You can put this solution on YOUR website!
Remember: \"Speed=distance%2Ftime\" ---> \"S=D%2Ft\"-------------> working eqn
\n" ); document.write( "\"Goose=GO=10%28mph%29%2Bx\" Speed of goose
\n" ); document.write( "\"BlueHeron=BH=x%28mph%29\" Speed of Blue Heron
\n" ); document.write( "In working eqn we get,
\n" ); document.write( "\"t%5BGO%5D=D%5BGO%5D%2FS%5BGO%5D\"; \"t%5BBH%5D=D%5BBH%5D%2FS%5BBH%5D\"
\n" ); document.write( "Since Goose and Blue Heron travel at the same \"time\"---> it cancels out, it's constant. And equating the 2 \"time\" equations:
\n" ); document.write( "\"D%5BGO%5D%2FS%5BGO%5D=D%5BBH%5D%2FS%5BBH%5D\"
\n" ); document.write( "\"120%2F%2810%2Bx%29=80%2Fx\", cross multiply
\n" ); document.write( "\"80%2810%2Bx%29=120x\"
\n" ); document.write( "\"800%2B80x=120x\"
\n" ); document.write( "\"800=120x-80x\"
\n" ); document.write( "\"800=40x\" -----> \"cross%28800%2920%2Fcross%2840%29=cross%2840%29x%2Fcross%2840%29\"
\n" ); document.write( "\"x=20mph\" ------------------------------------> Speed of Blue Heron
\n" ); document.write( "\"10%2Bx=10%2B20=30mph\" ---------------------------> speed of Goose
\n" ); document.write( "To check, going back working eqn, they should travel at the same \"time\" with their \"speed\" at their \"distance\":
\n" ); document.write( "\"t%5BBH%5D=80cross%28miles%29%2F%2820cross%28miles%29%2Fhr%29=4hrs\"
\n" ); document.write( "\"t%5BGO%5D=120cross%28miles%29%2F%2830cross%28miels%29%2Fhr%29=4hrs\"
\n" ); document.write( ":\"t%5BBH%5D=t%5BGO%5D\"
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
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