document.write( "Question 158644: The problem I am trying to figure out is: (a-2)^2=8 I have to use the square root property. I have no idea what I am doing wrong but this is what I have so far.sqrt[(a-2)^2]= +or-sqrt[8]
\n" ); document.write( "=a-2=+or-2
\n" ); document.write( "==a-2+2=3+or-2
\n" ); document.write( "a=3+or-2
\n" ); document.write( "a=3+2
\n" ); document.write( "a=5
\n" ); document.write( "or
\n" ); document.write( "a=3-2
\n" ); document.write( "a=1
\n" ); document.write( "Could you please tell me I have done wrong. And could you show the steps and explain this to me. I just don't understand. Thank you.
\n" ); document.write( "

Algebra.Com's Answer #116854 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
The problem I am trying to figure out is: (a-2)^2=8 I have to use the square root property. I have no idea what I am doing wrong but this is what I have so far.sqrt[(a-2)^2]= +or-sqrt[8]
\n" ); document.write( "=a-2=+or-2
\n" ); document.write( "==a-2+2=3+or-2
\n" ); document.write( "a=3+or-2
\n" ); document.write( "a=3+2
\n" ); document.write( "a=5
\n" ); document.write( "or
\n" ); document.write( "a=3-2
\n" ); document.write( "a=1
\n" ); document.write( "Could you please tell me I have done wrong. And could you show the steps and explain this to me. I just don't understand. Thank you.
\n" ); document.write( "----------------
\n" ); document.write( "Take the sqrt of both sides:
\n" ); document.write( "(a-2) = +/- sqrt(8) 2 is not the sqrt of 8.
\n" ); document.write( "So a = 2 + sqrt(8) and 2 - sqrt(8)
\n" ); document.write( "sqrt(8) is 2*sqrt(2), you can sub that in or not.\r
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