document.write( "Question 158644: The problem I am trying to figure out is: (a-2)^2=8 I have to use the square root property. I have no idea what I am doing wrong but this is what I have so far.sqrt[(a-2)^2]= +or-sqrt[8]
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document.write( "=a-2=+or-2
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document.write( "==a-2+2=3+or-2
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document.write( "a=3+or-2
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document.write( "a=3+2
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document.write( "a=5
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document.write( "or
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document.write( "a=3-2
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document.write( "a=1
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document.write( "Could you please tell me I have done wrong. And could you show the steps and explain this to me. I just don't understand. Thank you. \n" );
document.write( "
Algebra.Com's Answer #116854 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! The problem I am trying to figure out is: (a-2)^2=8 I have to use the square root property. I have no idea what I am doing wrong but this is what I have so far.sqrt[(a-2)^2]= +or-sqrt[8] \n" ); document.write( "=a-2=+or-2 \n" ); document.write( "==a-2+2=3+or-2 \n" ); document.write( "a=3+or-2 \n" ); document.write( "a=3+2 \n" ); document.write( "a=5 \n" ); document.write( "or \n" ); document.write( "a=3-2 \n" ); document.write( "a=1 \n" ); document.write( "Could you please tell me I have done wrong. And could you show the steps and explain this to me. I just don't understand. Thank you. \n" ); document.write( "---------------- \n" ); document.write( "Take the sqrt of both sides: \n" ); document.write( "(a-2) = +/- sqrt(8) 2 is not the sqrt of 8. \n" ); document.write( "So a = 2 + sqrt(8) and 2 - sqrt(8) \n" ); document.write( "sqrt(8) is 2*sqrt(2), you can sub that in or not.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |