document.write( "Question 158570: Ed invested twice as much in a 4% bond as he invested in a 3% bond. His total yearly interest from the two investments was $770. How much did he invest in each bond? \n" ); document.write( "
Algebra.Com's Answer #116843 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .04*2x+.03x=770 \n" ); document.write( ".08x+.03x=770 \n" ); document.write( ".11x=770 \n" ); document.write( "x=770/.11 \n" ); document.write( "x=7,000 invested @ 3% \n" ); document.write( "2*7,000=14,000 invested @ 4% \n" ); document.write( "Proof: \n" ); document.write( ".04*14,000+.03*7,000=770 \n" ); document.write( "560+210=770 \n" ); document.write( "770=770 \n" ); document.write( " |