document.write( "Question 158470: Find four consecutive even integers such that the sum of twice the fourth integer and half the second integer is 68. \n" ); document.write( "
Algebra.Com's Answer #116770 by checkley77(12844)\"\" \"About 
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X, X+2, X+4, X+6 ARE THE 4 EVEN INTEGERS.
\n" ); document.write( "2(X+6)+(X+2)/2=68
\n" ); document.write( "2X+12+(X+2)/2=68
\n" ); document.write( "2X+(X+2)/2=68-12
\n" ); document.write( "(2*2X+X+2)/2=56
\n" ); document.write( "(4X+X+2)/2=56
\n" ); document.write( "5X+2=2*56
\n" ); document.write( "5X=112-2
\n" ); document.write( "5X=110
\n" ); document.write( "X=110/5
\n" ); document.write( "X=22 THE FIRST INTEGER.
\n" ); document.write( "PROOF:
\n" ); document.write( "2(22+6)+(22+2)/2=68
\n" ); document.write( "2*28+24/2=68
\n" ); document.write( "56+12=68
\n" ); document.write( "68=68\r
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