document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=158512>Question 158512</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There are three consecutive even intergers. If twice the first integer added to the second is 268,262,find al three integers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #116762 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=116762\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2X+X+2=268,262<BR>\n" );
document.write( "3X=268,262-2<BR>\n" );
document.write( "3X=268,260<BR>\n" );
document.write( "X=268,260/3<BR>\n" );
document.write( "X=89,420 FOR THE SMALLEST INTEGER.<BR>\n" );
document.write( "89,420+2=89,422 FOR THE SECOND INTEGER.<BR>\n" );
document.write( "89,420=4=89,424 FOR THE THIRD INTEGER.<BR>\n" );
document.write( "2*89,420+89,422=268,262<BR>\n" );
document.write( "178,840+89,422=268,262<BR>\n" );
document.write( "268,262=268,262 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );