document.write( "Question 158308: If Eric had nineteen fewer nickels and twenty-one fewer dimes, he would have the same number of nickels, dimes, and quarters. Eric has a total of $7.45. How many of each coin does he have? \n" ); document.write( "
Algebra.Com's Answer #116689 by nerdybill(7384)\"\" \"About 
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If Eric had nineteen fewer nickels and twenty-one fewer dimes, he would have the same number of nickels, dimes, and quarters. Eric has a total of $7.45. How many of each coin does he have?
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\n" ); document.write( "Let q = number of quarters
\n" ); document.write( "then from: \"Eric had nineteen fewer nickels and twenty-one fewer dimes, he would have the same number of nickels, dimes, and quarters\" we get:
\n" ); document.write( "q+19 = number of nickels
\n" ); document.write( "q+21 = number of dimes
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\n" ); document.write( "Since, he has a total of $7.45 we get our formula:
\n" ); document.write( ".05(q+19) + .10(q+21) + .25q = 7.45
\n" ); document.write( ".05q + 0.95 + .10q + 2.1 + .25q = 7.45
\n" ); document.write( ".4q + 3.05 = 7.45
\n" ); document.write( ".4q = 4.4
\n" ); document.write( "q = 4.4/.4
\n" ); document.write( "q = 11 (this is the number of quarters)
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\n" ); document.write( "nickels:
\n" ); document.write( "q+19 = 11+19 = 30
\n" ); document.write( "dimes:
\n" ); document.write( "q+21 = 11+21 = 32 \n" ); document.write( "
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