document.write( "Question 22373: Hello, can anyone assist with this:\r
\n" ); document.write( "\n" ); document.write( "Obtain the value for v given that \r
\n" ); document.write( "\n" ); document.write( "S = 1.59t ^ (1-3v)\r
\n" ); document.write( "\n" ); document.write( "when S = 3.52 and t = 21.56\r
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Algebra.Com's Answer #11666 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
\"S+=+1.59t+%5E+%281-3v%29+\"
\n" ); document.write( "\"3.52+=+1.59%2A21.56+%5E+%281-3v%29+\"\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides by 1.59, but do NOT calculate and round off the value on the left side! This can cause serious error propagation.
\n" ); document.write( "\"3.52%2F1.59=21.56+%5E+%281-3v%29+\"\r
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\n" ); document.write( "\n" ); document.write( "Next, take the ln of both sides of the equation:
\n" ); document.write( "\"ln%283.52%2F1.59%29=+ln%2821.56+%5E+%281-3v%29+%29+\"\r
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\n" ); document.write( "\n" ); document.write( "Use the law of logarithms \"ln+M%5EN+=+N+%2Aln+M\":
\n" ); document.write( "\"ln%283.52%2F1.59%29=+%281-3v%29+%2Aln%2821.56+%29+\"\r
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\n" ); document.write( "\n" ); document.write( "Use the distributive property to remove the parentheses:
\n" ); document.write( "\"ln%283.52%2F1.59%29=+1%2Aln%2821.56%29+-3v+%2Aln%2821.56+%29+\"\r
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\n" ); document.write( "\n" ); document.write( "Subtract ln (21.56) from both sides:
\n" ); document.write( "\"ln%283.52%2F1.59%29-+1%2Aln%2821.56%29+=+-3v+%2Aln%2821.56+%29+\"\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides by -3ln(21.56):
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\n" ); document.write( "\n" ); document.write( "\"%28%28ln%283.52%2F1.59%29-+1%2Aln%2821.56%29%29%29%2F%28-3%2Aln%2821.56%29%29+=+v+\"\r
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\n" ); document.write( "\n" ); document.write( "Calculate with a calculator if you have one. I got v = 0.2470673563 approximately. It probably should be rounded off to v=0.247, since the problem is only accurate to three significant digits.\r
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\n" ); document.write( "\n" ); document.write( "You can check this by substituting all the numbers into the original equation and calculating the result to see if it really works. When I did this I found that my first attempt was WRONG!! This answer checks!!\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC\r
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