document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=22590>Question 22590</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2x+3y=8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #11662 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=11662\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> And you want to graph it?  You can either solve for y, and use the slope-intercept method, or you can find the two intercepts, graph the two points, and connect the points.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "By the slope-intercept method:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x+%2B+3y+=+8 ALIGN=MIDDLE  ALT=\"2x+%2B+3y+=+8\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+3y+=+-2x+%2B8 ALIGN=MIDDLE  ALT=\"+3y+=+-2x+%2B8\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%283y%29%2F3+=+%28-2%2F3%29x+%2B8%2F3+ ALIGN=MIDDLE  ALT=\"+%283y%29%2F3+=+%28-2%2F3%29x+%2B8%2F3+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "From this the y-intercept is 8/3 (almost 3) and the slope is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-2%2F3 ALIGN=MIDDLE  ALT=\"-2%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > (rise of -2 and run of 3, which means starting from the y-intercept, go DOWN 2 and RIGHT 3, and put the next point.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "By the x and y-intercept method:<BR>\n" );
document.write( "Let x= 0:  3y = 8, so <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=8%2F3 ALIGN=MIDDLE  ALT=\"y=8%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "\n" );
document.write( "Let y=0:  2x=8, so <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=4 ALIGN=MIDDLE  ALT=\"x=4\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
document.write( "\n" );
document.write( "Graph the points.  \r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Either way, it should look like this:\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28300%2C300%2C+-6%2C6%2C-6%2C6%2C+%28-2%2F3%29x%2B8%2F3%29 ALIGN=MIDDLE  ALT=\"+graph%28300%2C300%2C+-6%2C6%2C-6%2C6%2C+%28-2%2F3%29x%2B8%2F3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "R^2 at SCC \r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );