document.write( "Question 158239: Solve each inequality. Graph the solutions.\r
\n" ); document.write( "\n" ); document.write( "5|2b+1|-3< 7
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\n" ); document.write( "\n" ); document.write( "the < is like 7 is greater than or equal to
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Algebra.Com's Answer #116609 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"5%2Aabs%282b%2B1%29-3%3C=7\" Start with the given inequality\r
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\n" ); document.write( "\n" ); document.write( "\"5%2Aabs%282b%2B1%29%3C=10\" Add 3 to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"abs%282b%2B1%29%3C=2\" Divide both sides by 5\r
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\n" ); document.write( "\n" ); document.write( "Break up the absolute value (remember, if you have \"abs%28x%29%3C=+a\", then \"x+%3E=+-a\" and \"x+%3C=+a\")\r
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\n" ); document.write( "\n" ); document.write( "\"2b%2B1+%3E=+-2\" and \"2b%2B1+%3C=+2\" Break up the absolute value inequality using the given rule\r
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\n" ); document.write( "\n" ); document.write( "\"-2+%3C=+2b%2B1+%3C=+2\" Combine the two inequalities to get a compound inequality\r
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\n" ); document.write( "\n" ); document.write( "\"-3+%3C=+2b+%3C=+1\" Subtract 1 from all sides\r
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\n" ); document.write( "\n" ); document.write( "\"-3%2F2+%3C=+b+%3C=+1%2F2\" Divide all sides by 2 to isolate b\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So our answer is\r
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\n" ); document.write( "\n" ); document.write( "\"-3%2F2+%3C=+b+%3C=+1%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "So the answer in interval notation is []\r
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\n" ); document.write( "\n" ); document.write( "and the answer in set-builder notation is \r
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\n" ); document.write( "\n" ); document.write( "Here's the graph of the solution set\r
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\n" ); document.write( "\n" ); document.write( " Graph of the solution set\r
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\n" ); document.write( "\n" ); document.write( "Note:\r
\n" ); document.write( "\n" ); document.write( "There is a closed circle at \"b=-3%2F2+\" which means that we're including this value in the solution set\r
\n" ); document.write( "\n" ); document.write( "Also, there is a closed circle at \"b=+1%2F2\" which means that we're including this value in the solution set.
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