document.write( "Question 23158: I need help on figuring out the sides for triangle PQR. Coordinates given: P=(-2,6); Q=(-2,0); R=(5,0).\r
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Algebra.Com's Answer #11660 by rapaljer(4671) $\"\"$ $\"About$

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Normally you would need to use the distance formula to find the three distances between these points. However, comparing P(-2,6) and Q(-2,0), you can see that P is directly above Q, at a distance of 6 units. Comparing Q(-2,0) and R(5,0), you can see that these are both on the x axis at a distance of 7 units. Moreover, you can see that line PQ is perpendicular to line QR and the x-axis, so this is a right triangle. You can use the Theorem of Pythagoras to find PR = $\"sqrt%28%286%5E2+%2B7%5E2%29%29+=+sqrt%28%2836%2B49%29%29=sqrt%2885%29+\"$ .\r
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