document.write( "Question 158134This question is from textbook Organic Chemistry
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document.write( ": This question is actually an example problem (not explained) from a chemistry book, but I cannot remember my log rules.
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document.write( "pKa = - log10 Ka
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document.write( "If Ka = 1.8 * 10^-5 , then we should be able to find the pKa. (The answer is given b/c it's a sample, pKa = 4.7)
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document.write( "Mathematically: x = - log10 (1.8 *10^-5)
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document.write( "I don't understand what to do with the - sign in front of the log, to solve the log, one would say 10^ (1.8 * 10^-5), but then something must happen with the negative sign to give the answer of 4.7...
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document.write( "Also, how do you go backwards (given pKa, solve for Ka).
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document.write( "Same example: 4.7 = -log10 Ka
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document.write( "so, 10 ^ x = 4.7 ?
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document.write( "Then, I am lost.
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document.write( "Thank you.
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Algebra.Com's Answer #116532 by edjones(8007)![]() ![]() You can put this solution on YOUR website! log(1.8*10^-5)=-4.7... \n" ); document.write( "-log(1.8*10^-5)=4.7... \n" ); document.write( ". \n" ); document.write( "-4.7=log(1.8*10^-5) \n" ); document.write( "10^-4.7=10^log(1.8*10^-5) \n" ); document.write( "0.0000199526...=1.8*10-5 This is not exactly correct but you get the idea. \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |