document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=158131>Question 158131</A>: <I><SPAN STYLE=\"word-break: break-all;\"> . If a vendor charges p dollars each for rugby shirts, then he expects to sell 2000 - 100p shirts at a tournament.<BR>\n" );
document.write( "a) Find a polynomial R(p) that represents the total revenue when the shirts are p dollars each.<BR>\n" );
document.write( "b) Find R(5), R(10), and R(20).<BR>\n" );
document.write( "c) Use the bar graph to determine the price that will give the maximum total revenue<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #116519 by </B><A HREF=/tutors/aboutme.mpl?userid=joey_quizan><B>joey_quizan(15)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=joey_quizan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=116519\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Sol:\r<BR>\n" );
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document.write( "p = unit price in dollar of a rugby shirt\r<BR>\n" );
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document.write( "2000-100p = number of unit that he expect to sell\r<BR>\n" );
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document.write( "R(p) = Total revenue\r<BR>\n" );
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document.write( "R(p) = p(2000-100p)<BR>\n" );
document.write( "R(p) = 2000p - 100p^2<BR>\n" );
document.write( "Ans to a: R(p) = 2000p - 100p^2\r<BR>\n" );
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document.write( "For b:\r<BR>\n" );
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document.write( "R(5) = 2000x5-100x5x5<BR>\n" );
document.write( "R(5) = 10000-2500<BR>\n" );
document.write( "R(5) = 7500\r<BR>\n" );
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document.write( "R(10) = 2000x10-100x10x10<BR>\n" );
document.write( "R(10) = 20000-10000<BR>\n" );
document.write( "R(10) = 10000\r<BR>\n" );
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document.write( "R(20) = 2000x20-100x20x20<BR>\n" );
document.write( "R(20) = 40000-40000<BR>\n" );
document.write( "R(20) = 0\r<BR>\n" );
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document.write( "For c:\r<BR>\n" );
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document.write( "Max R(p) = 10000\r<BR>\n" );
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