document.write( "Question 158089: I have many problems like this one but some are linear,quadratic,cubic,
\n" ); document.write( "well the 1st problem is linear. Y=-2x+1 so we have to graph it and identify the domain and range. I've graphed it but I havent figured out how to find the domain and range. I've tried on other problems...x>0 stuff like that but i dont know if its right. Ive tried going over it a hundred times and even tried looking online on how to identify domain and range...but nothing helps... I'm really struggling with this and 39 other problems just like it.
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Algebra.Com's Answer #116495 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
The domain is given as all values of x where the function exists. Generally, you look for things that are 'not allowed'. Things like dividing by zero or the square root of a negative number will result in non-real results. So, any value of x that makes things like that happen are excluded from the range.\r
\n" ); document.write( "\n" ); document.write( "In the case of \"y+=+-2x+%2B1\" there are no real value of x that result in a non-real value of y. So, the domain is \"all x\" and the range is 'all y'. That is, there are no invalid answers for this one.\r
\n" ); document.write( "\n" ); document.write( "For the other problems you have, look for things like I noted above. If for instance, you are given \"y+=+1%2Fx\", then the when x=0, the value for y is undefined. So the domain there would be \"all x except 0\", and the range would be 'all y'.\r
\n" ); document.write( "\n" ); document.write( "For something like \"y+=+sqrt%28x%29\", since you can't have a real square root of a negative number, the range would be \"all x >= 0\". Since square roots can be both negative and poistive, the range is \"all y\".\r
\n" ); document.write( "\n" ); document.write( "Hope this helps
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