document.write( "Question 158070This question is from textbook prentice hall mathematics algebra 1
\n" ); document.write( ": a passenger train's speed is 60 mi/h, and a freight train's speed is 40 mi/h. the passenger train travels the same distance in 1.5 h less time than the freight train. How long does each train take to make the trip?\r
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Algebra.Com's Answer #116468 by mangopeeler07(462)\"\" \"About 
You can put this solution on YOUR website!
h=amount of hours\r
\n" ); document.write( "\n" ); document.write( "mph(h)=distance\r
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\n" ); document.write( "\n" ); document.write( "the passenger train travels the same distance (set equal to each other) in 1.5 h less time than the freight train.\r
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\n" ); document.write( "\n" ); document.write( "\"%2860%2Fh%29%28h-1.5%29=%2840%2Fh%29%28h%29\"\r
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\n" ); document.write( "\n" ); document.write( "Simplify each side by multiplying
\n" ); document.write( "\"%28%2860h-90%29%2Fh%29=%2840h%2Fh%29\"\r
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\n" ); document.write( "\n" ); document.write( "Eliminate the denominators, since they are the same thing
\n" ); document.write( "\"60h-90=40h\"\r
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\n" ); document.write( "\n" ); document.write( "Subtract 60h from both sides
\n" ); document.write( "\"-90=-20h\"\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides by -20
\n" ); document.write( "\"4.5=h\"\r
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\n" ); document.write( "\n" ); document.write( "Passenger train: (h-1.5)
\n" ); document.write( "Freight train: (h)\r
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\n" ); document.write( "\n" ); document.write( "Plug in 4.5 for h\r
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\n" ); document.write( "\n" ); document.write( "4.5-1.5=3.0
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\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "Passenger train= 3 hours
\n" ); document.write( "Freight train= 4.5 hours
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