document.write( "Question 158041: please help me:\r
\n" ); document.write( "\n" ); document.write( "the sum of the digits of a two-digit number is 12. if the digits are reversed, the new number is 15 more than twice the original number. what is the original number?
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Algebra.Com's Answer #116451 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let t=tens digit and u=units digit\r
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\n" ); document.write( "\n" ); document.write( "ANY two digit number can be written in the form of: tens_digit*10+units_digit\r
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\n" ); document.write( "\n" ); document.write( "Algebraically this looks like: \"n=10t%2Bu\" where \"n\" is any two digit number\r
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\n" ); document.write( "\n" ); document.write( "If you reverse the digits of \"n\" you get \"m=10u%2Bt\" where \"m\" is the reversed number (ie if n=27 then m=72)\r
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\n" ); document.write( "\n" ); document.write( "Since the \"sum of the digits of a two-digit number is 12\", this means that \"t%2Bu=12\"\r
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\n" ); document.write( "\n" ); document.write( "Also, since the \"new number is 15 more than twice the original number\", this tells us that \"10u%2Bt=2%2810t%2Bu%29%2B15\"\r
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\n" ); document.write( "\n" ); document.write( "\"10u%2Bt=20t%2B2u%2B15\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"10u%2Bt-20t-2u=15\" Subtract \"20t\" from both sides. Subtract \"2u\" from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"8u-19t=15\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"-19t%2B8u=15\" Rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "So we have the system:\r
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\n" ); document.write( "\n" ); document.write( "\"system%28t%2Bu=12%2C-19t%2B8u=15%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"19%28t%2Bu%29=19%2812%29\" Multiply the both sides of the first equation by 19.\r
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\n" ); document.write( "\n" ); document.write( "\"19t%2B19u=228\" Distribute and multiply.\r
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\n" ); document.write( "\n" ); document.write( "So we have the new system of equations:\r
\n" ); document.write( "\n" ); document.write( "\"system%2819t%2B19u=228%2C-19t%2B8u=15%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now add the equations together. You can do this by simply adding the two left sides and the two right sides separately like this:\r
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\n" ); document.write( "\n" ); document.write( "\"%2819t%2B19u%29%2B%28-19t%2B8u%29=%28228%29%2B%2815%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%2819t%2B-19t%29%2B%2819u%2B8u%29=228%2B15\" Group like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"0t%2B27u=243\" Combine like terms. Notice how the x terms cancel out.\r
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\n" ); document.write( "\n" ); document.write( "\"27u=243\" Simplify.\r
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\n" ); document.write( "\n" ); document.write( "\"u=%28243%29%2F%2827%29\" Divide both sides by \"27\" to isolate \"u\".\r
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\n" ); document.write( "\n" ); document.write( "\"u=9\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "\"19t%2B19u=228\" Now go back to the first equation.\r
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\n" ); document.write( "\n" ); document.write( "\"19t%2B19%289%29=228\" Plug in \"u=9\".\r
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\n" ); document.write( "\n" ); document.write( "\"19t%2B171=228\" Multiply.\r
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\n" ); document.write( "\n" ); document.write( "\"19t=228-171\" Subtract \"171\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"19t=57\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"t=%2857%29%2F%2819%29\" Divide both sides by \"19\" to isolate \"t\".\r
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\n" ); document.write( "\n" ); document.write( "\"t=3\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"t=3\" and \"u=9\".\r
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\n" ); document.write( "\n" ); document.write( "This means that the original number is \"n=10%283%29%2B9=39\" and the new number is \"m=10%289%29%2B3=93\"
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