document.write( "Question 158031This question is from textbook
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\n" ); document.write( "\n" ); document.write( "Find an equation of the line having the given characteristics. Write the equation using the general form or the slope-intercept form, whichever you prefer. Graph each line.\r
\n" ); document.write( "\n" ); document.write( "9. Slope = -3; containing the point (2, -1)
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\n" ); document.write( " y = -3x - 1 this is where I started
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Algebra.Com's Answer #116442 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
First let's find the equation of the line \r
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\n" ); document.write( "\n" ); document.write( "If you want to find the equation of line with a given a slope of \"-3\" which goes through the point (2,-1), you can simply use the point-slope formula to find the equation:\r
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\n" ); document.write( "\n" ); document.write( "---Point-Slope Formula---\r
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\n" ); document.write( "\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where \"m\" is the slope, and is the given point\r
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\n" ); document.write( "\n" ); document.write( "So lets use the Point-Slope Formula to find the equation of the line\r
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\n" ); document.write( "\n" ); document.write( "\"y--1=%28-3%29%28x-2%29\" Plug in \"m=-3\", \"x%5B1%5D=2\", and \"y%5B1%5D=-1\" (these values are given)\r
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\n" ); document.write( "\n" ); document.write( "\"y%2B1=%28-3%29%28x-2%29\" Rewrite \"y--1\" as \"y%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "\"y%2B1=-3x%2B%28-3%29%28-2%29\" Distribute \"-3\"\r
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\n" ); document.write( "\n" ); document.write( "\"y%2B1=-3x%2B6\" Multiply \"-3\" and \"-2\" to get \"6\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=-3x%2B6-1\" Subtract 1 from both sides to isolate y\r
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\n" ); document.write( "\n" ); document.write( "\"y=-3x%2B5\" Combine like terms \"6\" and \"-1\" to get \"5\" \r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the equation of the line with a slope of \"-3\" which goes through the point (2,-1) is:\r
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\n" ); document.write( "\n" ); document.write( "\"y=-3x%2B5\" which is now in \"y=mx%2Bb\" form where the slope is \"m=-3\" and the y-intercept is \"b=5\"\r
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\n" ); document.write( "\n" ); document.write( "Since \"b=5\" this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis\r
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\n" ); document.write( "\n" ); document.write( "So we have one point \r
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\n" ); document.write( "\n" ); document.write( "Now since the slope is comprised of the \"rise\" over the \"run\" this means\r
\n" ); document.write( "\n" ); document.write( "\"slope=rise%2Frun\"\r
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\n" ); document.write( "\n" ); document.write( "Also, because the slope is \"-3\", this means:\r
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\n" ); document.write( "\n" ); document.write( "\"rise%2Frun=-3%2F1\"\r
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\n" ); document.write( "\n" ); document.write( "which shows us that the rise is -3 and the run is 1. This means that to go from point to point, we can go down 3 and over 1\r
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\n" ); document.write( "\n" ); document.write( "So starting at , go down 3 units \r
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\n" ); document.write( "\n" ); document.write( "and to the right 1 unit to get to the next point \r
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\n" ); document.write( "\n" ); document.write( "Now draw a line through these points to graph \"y=-3x%2B5\"\r
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\n" ); document.write( "\n" ); document.write( " So this is the graph of \"y=-3x%2B5\" through the points and \r
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\n" ); document.write( "\n" ); document.write( "Also, notice how the graph has a slope of -3 (since \"m=-3\") and it goes through the point (2,-1).
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