document.write( "Question 158017: Different Weights. Professor Williamson counts his midterm as 2/3 of the grade and his final as 1/3 of the grade. Wendy scored only 48 on the midterm. What range of scores on the final exam would put Wendy’s average between 70 and 79 inclusive? \r
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Algebra.Com's Answer #116434 by jojo14344(1513) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"x=Midterm\"$
\n" ); document.write( " $\"y=FinalExam\"$
\n" ); document.write( "Let's start with an average of 70 (MIN) first:
\n" ); document.write( "Given $\"x=48\"$
\n" ); document.write( " $\"%282%2F3%29x%2B%281%2F3%29y=70\"$
\n" ); document.write( " $\"%282%2F3%29%2848%29%2B%281%2F3%29y=70\"$
\n" ); document.write( " $\"%2896%2F3%29%2B%281%2F3%29y=70\"$
\n" ); document.write( " $\"%281%2F3%29y=70-%2896%2F3%29=70-32=38\"$ , cross multiply
\n" ); document.write( " $\"y=%2838%29%283%29=114\"$ , MINIMUM SCORE on Final Exam
\n" ); document.write( "Next with an average of 79 (MAX): Given $\"x=48\"$
\n" ); document.write( " $\"%282%2F3%29x%2B%281%2F3%29y=79\"$
\n" ); document.write( " $\"%282%2F3%29%2848%29%281%2F3%29y=79\"$
\n" ); document.write( " $\"%281%2F3%29y=79-%2896%2F3%29=79-32=47\"$ , cross multiply
\n" ); document.write( " $\"y=3%2A47=141\"$ , MAX SCORE on Final Exam
\n" ); document.write( "Therefore:To have an average of $\"70-79\"$ inclusive, he should have a final score of $\"114-141\"$ inclusive.
\n" ); document.write( "Check it out by substituting 1st $\"y=114\"$ , 2nd $\"y=141\"$ to the above eqn and you'll get an average of 70 and 79 inclusive.
\n" ); document.write( "thank you,
\n" ); document.write( "jojo
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