document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=21531>Question 21531</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The diameter of a conical paper cup is 3.5 inches, and the length of the sloping side is 4.55 inches. How much water will the cup hold? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #11643 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=11643\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The diameter of a conical paper cup is 3.5 inches, and the length of the sloping side is 4.55 inches. How much water will the cup hold?<BR>\n" );
document.write( "VOLUME OF A CONE = V  =PI*R*R*H/3<BR>\n" );
document.write( "WE HAVE DIAMETER=3.5 INCHES...HENCE RADIUS =3.5/2=1.75 INCHES<BR>\n" );
document.write( "SLANT LENGTH =L=4.55<BR>\n" );
document.write( "FROM PYTHOGARUS THEOREM WE HAVE L*L=H*H+R*R<BR>\n" );
document.write( "4.55*4.55=H*H+1.75*1.75<BR>\n" );
document.write( "H*H=4.55*4.55-1.75*1.75=(4.55+1.75)(4.55-1.75)=6.3*2.8=(3*3*0.7)*(0.7*2*2)<BR>\n" );
document.write( "H=3*0.7*2=4.2<BR>\n" );
document.write( "HENCE V=PI*1.75*1.75*4.2/3=13.475 CUBIC INCHES<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );