document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=157933>Question 157933</A>: <I><SPAN STYLE=\"word-break: break-all;\"> CAN SOMEONE PLEASE HELP ME WITH THIS PROBLEM:\r<BR>\n" );
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document.write( "R(x)= x^3 - 2x^2 - 7 / x^6 - 2x^5 + 6x^2 - 4. How many vertical asymptotes are possible? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #116417 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=116417\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Notice how the degree of the denominator is 6. So this means that there are a max of 6 real zeros possible for <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E6+-+2x%5E5+%2B+6x%5E2+-+4 ALIGN=MIDDLE  ALT=\"x%5E6+-+2x%5E5+%2B+6x%5E2+-+4\"   DISABLED_style= \"max-width:90%; height:auto;\" >. So this means that there are a max of 6 vertical asymptotes possible (since each zero of a denominator results in division by zero). </SPAN>\n" );
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