document.write( "Question 157970This question is from textbook Algebra 1
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document.write( ": 7=6(2z=3)-5 \n" );
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Algebra.Com's Answer #116387 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! ONE TOO MANY = SIGNS. \n" ); document.write( "CORRECT & RESUBMIT. \n" ); document.write( "UNLESS THE SECOND = SIGN (2Z=3) SHOULD BE A + SIGN THEN: \n" ); document.write( "7=12Z+18-5 \n" ); document.write( "12Z=7-18+5 \n" ); document.write( "12Z=-6 \n" ); document.write( "Z=-6/12 \n" ); document.write( "Z=-1/5 OR -.5 \n" ); document.write( "PROOF: \n" ); document.write( "7=12*-.5+18-5 \n" ); document.write( "7=-6+18-5 \n" ); document.write( "7=18-11 \n" ); document.write( "7=7 \n" ); document.write( " \n" ); document.write( " |