document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=157977>Question 157977</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 136m. The length is 8m more than twice the width. Find the dimensions?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #116386 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=116386\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=2W+8 FOR THE LENGTH.<BR>\n" );
document.write( "W=THE WIDTH.<BR>\n" );
document.write( "2(2W+8)+2W=136<BR>\n" );
document.write( "4W+16+2W=136<BR>\n" );
document.write( "6W=136-16<BR>\n" );
document.write( "6W=120<BR>\n" );
document.write( "W=120/6<BR>\n" );
document.write( "W=20 FOR THE WIDTH<BR>\n" );
document.write( "L=2*20+8=40+8=48 FOR THE LENGTH.<BR>\n" );
document.write( "pROOF<BR>\n" );
document.write( "2*48+2*20=136<BR>\n" );
document.write( "96+40=136<BR>\n" );
document.write( "136=136 </SPAN>\n" );
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