document.write( "Question 157928: Evaluate 10/x + 2 when x=3 \n" ); document.write( "
Algebra.Com's Answer #116371 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "Simply substitute the x with a 3 and solve:
\n" ); document.write( "Starting with the equation:
\n" ); document.write( "10/x + 2
\n" ); document.write( ".
\n" ); document.write( "Plugging in our value of x:
\n" ); document.write( "10/3 + 2
\n" ); document.write( "= 10/3 + 6/3
\n" ); document.write( "= 16/3
\n" ); document.write( "
\n" );