document.write( "Question 157884: pump A working together with pump B can drain a tank of water in 5 hours.
\n" ); document.write( "pump A working alone can drain the tank in T hours.
\n" ); document.write( "pump B working alone can drain the pump in (T-4) hours.
\n" ); document.write( "how long does it take for pump A to drain the tank by itself?
\n" ); document.write( "how long does it take for pump B to drain the tank by itself?
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Algebra.Com's Answer #116354 by jojo14344(1513)\"\" \"About 
You can put this solution on YOUR website!
\"P%5Ba%5D%2BP%5Bb%5D=5hours\" ----------------------> working eqn
\n" ); document.write( "Also, \"P%5Ba%5D=T%5Bhr%5D\", \"P%5Bb%5D=%28T-4%29%5Bhr%5D\"
\n" ); document.write( "Substitute in working eqn:
\n" ); document.write( "\"T%2B%28T-4%29=5hours\"
\n" ); document.write( "\"2T=5%2B4=9\" ----> \"cross%282%29T%2Fcross%282%29=9%2F2\"
\n" ); document.write( "\"T=4.5hours\" ---------------------------> for \"Pump%5Ba%5D\"
\n" ); document.write( "\"T-4=4.5-4=0.5hour\" --------------------> for \"Pump%5Bb%5D\"
\n" ); document.write( "In doubt? go back working eqn:
\n" ); document.write( "\"4.5hrs%2B0.5hr=5hours\"
\n" ); document.write( "\"5hours=5hours\"
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
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