document.write( "Question 157882: Two angles are supplementary of each other. Twice one angle is equal to the other angle minus the product of six and eight.
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\n" ); document.write( "Set up a system of linear equations to represent the two angles. Graph each of the equations on one rectangular coordinate system. (Hint: You must get y by itself before graphing.)
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Algebra.Com's Answer #116336 by gonzo(654)\"\" \"About 
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A = angle A and B = angle B.
\n" ); document.write( "A + B = 180 (supplementary)
\n" ); document.write( "2*A = B-48
\n" ); document.write( "A = (B-48)/2
\n" ); document.write( "(B-48)/2 + B = 180
\n" ); document.write( "B-48 + 2B = 360
\n" ); document.write( "3B = 408
\n" ); document.write( "B = 136
\n" ); document.write( "A = 180-136 = 44
\n" ); document.write( "tangent of angle B = y / x = -.965688775
\n" ); document.write( "y = -.965688775 * x
\n" ); document.write( "let x = -5, then y = -.965688775 * (-5) =
\n" ); document.write( "graph of the line formed by A = 136 degrees is as follows:
\n" ); document.write( "graph \"+%28600%2C600%2C-5%2C0%2C0%2C5%2C%28-.96568875%29%2Ax%29\"
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