document.write( "Question 157882: Two angles are supplementary of each other. Twice one angle is equal to the other angle minus the product of six and eight.
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document.write( "Set up a system of linear equations to represent the two angles. Graph each of the equations on one rectangular coordinate system. (Hint: You must get y by itself before graphing.) \n" );
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Algebra.Com's Answer #116336 by gonzo(654)![]() ![]() ![]() You can put this solution on YOUR website! A = angle A and B = angle B. \n" ); document.write( "A + B = 180 (supplementary) \n" ); document.write( "2*A = B-48 \n" ); document.write( "A = (B-48)/2 \n" ); document.write( "(B-48)/2 + B = 180 \n" ); document.write( "B-48 + 2B = 360 \n" ); document.write( "3B = 408 \n" ); document.write( "B = 136 \n" ); document.write( "A = 180-136 = 44 \n" ); document.write( "tangent of angle B = y / x = -.965688775 \n" ); document.write( "y = -.965688775 * x \n" ); document.write( "let x = -5, then y = -.965688775 * (-5) = \n" ); document.write( "graph of the line formed by A = 136 degrees is as follows: \n" ); document.write( "graph |