document.write( "Question 157876: I've been working on an assignment and I'm stumped. I have to solve quadratic equations with the following steps:
\n" ); document.write( "a) Move the constant term to the right side of the equation.
\n" ); document.write( "b) Multiply each term in the equation by four times the coefficient of the x2 term.
\n" ); document.write( "c) Square the coefficient of the original x term and add it to both sides of the equation.
\n" ); document.write( "d) Take the square root of both sides.
\n" ); document.write( "3) Set the left side of the equation equal to the positive square root of the number on the right side and solve for x.
\n" ); document.write( "f) Set the left side of the equation equal to the negative square root of thenumber on the right side of the euqation and solve for x.\r
\n" ); document.write( "\n" ); document.write( "I have two equations I'm stuck on:
\n" ); document.write( "1) x2 - 2x - 13 = 0
\n" ); document.write( "2) 2x2 - 3x - 5 = 0
\n" ); document.write( "

Algebra.Com's Answer #116327 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
a) Move the constant term to the right side of the equation.
\n" ); document.write( "1)\"+x%5E2+-+2x+-+13+=+0\"
\n" ); document.write( " \"x%5E2+-+2x+=+13\" \r
\n" ); document.write( "\n" ); document.write( "b) Multiply each term in the equation by four times the coefficient of the \"x%5E2\" term.
\n" ); document.write( "the coefficient of the \"x%5E2\" is \"1\" and four times the coefficient will be \"4%2A1=4\", so you will have:
\n" ); document.write( "\"x%5E2%2A4+-+2x%2A4+=+13%2A4\"
\n" ); document.write( "\"4x%5E2+-+8x+=+52\"\r
\n" ); document.write( "\n" ); document.write( "c) Square the coefficient of the original \"x+\"term and add it to both sides of the equation.
\n" ); document.write( "the coefficient of the original \"x+\"term is \"-2\"
\n" ); document.write( "\"4x%5E2+-+8x+%2B+%28-2%29%5E2++=+52+%2B+%28-2%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"4x%5E2+-+8x+%2B+4+=+52+%2B+4\"…then you have
\n" ); document.write( "\"4x%5E2+-+8x+%2B+4+=+56\"
\n" ); document.write( "\"%282x-2%29%5E2=+56\"\r
\n" ); document.write( "\n" ); document.write( "d) Take the square root of both sides.\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%28%282x-2%29%5E2%29\" = +-\"sqrt%2856%29\"
\n" ); document.write( "\"2x-2\" = +-\"%287.48%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "e) Set the left side of the equation equal to the positive square root of the number on the right side and solve for \"x\".\r
\n" ); document.write( "\n" ); document.write( "\"2x-2+=+7.48\"
\n" ); document.write( "\"2x+=+7.48%2B2\"
\n" ); document.write( "\"2x+=+9.48\"
\n" ); document.write( "\"x+=+9.48%2F2\"
\n" ); document.write( "\"x+=+4.74\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "f) Set the left side of the equation equal to the negative square root of the number on the right side of the equation and solve for \"x\". \r
\n" ); document.write( "\n" ); document.write( "\"2x-2+=+-7.48\"
\n" ); document.write( "\"2x+=+-7.48%2B2\"
\n" ); document.write( "\"2x+=+-5.48\"
\n" ); document.write( "\"x+=+-5.48%2F2\"
\n" ); document.write( "\"x+=+-2.74\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "2) \"2x%5E2+-+3x+-+5+=+0\"\r
\n" ); document.write( "\n" ); document.write( "a) Move the constant term to the right side of the equation.
\n" ); document.write( "\"2x%5E2+-+3x+=+5+\"\r
\n" ); document.write( "\n" ); document.write( "b) Multiply each term in the equation by four times the coefficient of the \"x%5E2\" term.
\n" ); document.write( "the coefficient of the \"x%5E2\" is \"2\" and four times the coefficient will be \"4%2A2=+8\", so you will have:\r
\n" ); document.write( "\n" ); document.write( "\"2x%5E2%2A8+-+3x%2A8+=+5%2A8+\"\r
\n" ); document.write( "\n" ); document.write( "\"16x%5E2+-24%2Ax+=+40+\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "c) Square the coefficient of the original \"x+\"term and add it to both sides of the equation.
\n" ); document.write( "the coefficient of the original \"x+\"term is \"-3\"
\n" ); document.write( "\"16x%5E2+-+24x+%2B+%28-3%29%5E2+=+40+%2B++%28-3%29%5E2+\"
\n" ); document.write( "\"16x%5E2+-+24x+%2B+9+=+40+%2B++9+\"
\n" ); document.write( "\"16x%5E2+-+24x+%2B+9+=+49+\"\r
\n" ); document.write( "\n" ); document.write( "\"%284x-3%29%5E2=+49\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "d) Take the square root of both sides\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%28%284x-3%29%5E2%29=+sqrt%2849%29\"\r
\n" ); document.write( "\n" ); document.write( "\"4x-3\" = +-\"%287%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "e) Set the left side of the equation equal to the positive square root of the number on the right side and solve for \"x\".\r
\n" ); document.write( "\n" ); document.write( "\"4x-3\" = +\"%287%29\"
\n" ); document.write( "\"4x+=+7%2B3+\"
\n" ); document.write( "\"4x+=+10+\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+10%2F4\"
\n" ); document.write( "\"x+=+2.5\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "f) Set the left side of the equation equal to the negative square root of the number on the right side of the equation and solve for \"x\".\r
\n" ); document.write( "\n" ); document.write( "\"4x-3\" = -\"%287%29\"
\n" ); document.write( "\"4x+=+-7%2B3+\"
\n" ); document.write( "\"4x+=+-4+\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+-4%2F4\"
\n" ); document.write( "\"x+=+-1\"\r
\n" ); document.write( "\n" ); document.write( "
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