document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=23146>Question 23146</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (x-2)(2x+1)(2x-3)>0<BR>\n" );
document.write( "find the range of x ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #11627 by </B><A HREF=/tutors/aboutme.mpl?userid=khwang><B>khwang(438)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=khwang><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=11627\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  (x-2)(2x+1)(2x-3)>0<BR>\n" );
document.write( "find the range of x ?<BR>\n" );
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document.write( " There are three roots of (x-2)(2x+1)(2x-3) = 0,namely 2, 3/2 and -1/2 <BR>\n" );
document.write( " (in descending order).\r<BR>\n" );
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document.write( " Hence,  (x-2)(2x+1)(2x-3)>0 --> x >2 or  -1/2 < x < 3/2.\r<BR>\n" );
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document.write( " That is, the solution set of (x-2)(2x+1)(2x-3)>0 is<BR>\n" );
document.write( " (-1/2, 3/2) U (2, +oo) .\r<BR>\n" );
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document.write( " Draw a diagram on the real line you will see. \r<BR>\n" );
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document.write( " Kenny<BR>\n" );
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document.write( "  </SPAN>\n" );
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