document.write( "Question 157797: If there is a plot of land that is 24 by 30. And surrounding the land is a walkway that has an area of 247 ft. sq. what is the width of the walkway. \n" ); document.write( "
Algebra.Com's Answer #116260 by checkley77(12844)\"\" \"About 
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To understand this problem you should sketch/draw a 24 by 30 rectangle.
\n" ); document.write( "Then draw a larger rectangle on the outside of this rectangle representing the walkway.
\n" ); document.write( "Now assign the value x to the width of the sidewalk.
\n" ); document.write( "You now have a rectangle with dimensions of (24+2x) & (30+2x)
\n" ); document.write( "Calculate the area of the inner rectangle (the plot)+& add the additional 247 ft^2 & solve the equation.
\n" ); document.write( "---------------------------------------------------------------------
\n" ); document.write( "24*30=720 ft^2 for the plot.
\n" ); document.write( "(24+2x)(30+2x)=720+247
\n" ); document.write( "720+60x+48x+4x^2=967
\n" ); document.write( "4x^2+108x+720-967=0
\n" ); document.write( "4x^2+108x-247=0
\n" ); document.write( "Using the quadratic equation:\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"we get:
\n" ); document.write( "x=(-108+-sqrt[108^2-4*4*-247])/2*4
\n" ); document.write( "x=(-108+-sqrt[11,664+3,952]) /8
\n" ); document.write( "x=(-108+-sqrt15,616)/8
\n" ); document.write( "x=(-109+-124.964)/8
\n" ); document.write( "x=(-108+124.964)/8
\n" ); document.write( "x=16.964/8
\n" ); document.write( "x=2.12 feet is the width of the walkway.
\n" ); document.write( "Proof:
\n" ); document.write( "(24+2*2.12)(30+2*2.12)=967
\n" ); document.write( "(24+4.24)(30+4.24)=967
\n" ); document.write( "28.24*34.24=967
\n" ); document.write( "967=967 \n" ); document.write( "
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