document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=157716>Question 157716</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The speed of the current in the RAnge River is 3 mph.   Marie can kayak 4 miles upstream in the same amount of time it takes her to kayak 10 miles downstream.  What is the speek of the kayak if traveling in calm water? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #116251 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=116251\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "4=(S-3)T OR T=4/(S-3)<BR>\n" );
document.write( "10=(S+3)T OR T=10/(S+3)<BR>\n" );
document.write( "4/(S-3)=10/(S-3) CROSS MULTIPLY<BR>\n" );
document.write( "10(S-3)=4(S+3)<BR>\n" );
document.write( "10S-30=4S+12<BR>\n" );
document.write( "10S-4S=12+30<BR>\n" );
document.write( "6S=42<BR>\n" );
document.write( "S=42/6<BR>\n" );
document.write( "S=7 MPH FOR THE CANOE IN CALM WATER.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "4/(7-3)=10/(7+3)<BR>\n" );
document.write( "4/4=10/10<BR>\n" );
document.write( "1=1\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );