document.write( "Question 157772: Find four consecutive integers such that twice the first subtracted from the sum of the other three integers is sixteen. \n" ); document.write( "

Algebra.Com's Answer #116246 by jojo14344(1513) $\"\"$ $\"About$

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Let 肝= 1st integer
\n" ); document.write( "x+1 = 2nd integer
\n" ); document.write( "x+2 = 3rd integer
\n" ); document.write( "x+3 = 4th integer
\n" ); document.write( "Then, (x+1+x+2+x+3)-2x=16 ----------------------- condition, twice the 1st is subtracted from the sum of 2nd, 3rd & 4th:
\n" ); document.write( "continuing;
\n" ); document.write( "3x-2x=16-6
\n" ); document.write( "x=10 ------------------------------------- 1st integer
\n" ); document.write( "10+1=11 ---------------------------------- 2nd integer
\n" ); document.write( "10+2=12 ---------------------------------- 3rd integer
\n" ); document.write( "10+3=13 ---------------------------------- 4th integer
\n" ); document.write( "To check, go back to the condition:
\n" ); document.write( "11+12+13-2(10)=16
\n" ); document.write( "36-20=16
\n" ); document.write( "16=16
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo \n" ); document.write( "

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