document.write( "Question 11267: John has 7 more pennies than nickels and 2 fewer quarters than pennies. His total amount of money is $2.87. How many of each type of coin does he have? \n" ); document.write( "
Algebra.Com's Answer #11624 by stanbon!(97)![]() ![]() ![]() You can put this solution on YOUR website! Let number of nickels be \"x\". \n" ); document.write( "Then number of pennies is \"x+7\" \n" ); document.write( "And number of quarters is \"x+7-2\" = \"x+5\" \n" ); document.write( "Value of nickels is (5)x cents \n" ); document.write( "Value of pennies is (1)(x+7)= x+7 cents \n" ); document.write( "Value of quarters is (25)(x+5)= 25x+125 cents \n" ); document.write( "EQUATION: \n" ); document.write( " Value of nickels + Value of pennies + Value of quarters = 287 cents \n" ); document.write( " 5x + x+7 + 25x+125 = 287 \n" ); document.write( " 31x = 155 \n" ); document.write( " x = 5 (number of nickels) \n" ); document.write( " x+7 = 12 (number of pennies) \n" ); document.write( " x+5 = 10 (number of quarters) \n" ); document.write( " |