document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=157698>Question 157698</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two pumps of different sizes, working together, can empty a fuel tank in 5 hours. The larger pump can empty this tank in 4 hours less time than the smaller. If the larger pump is out of order, how long will it take the smaller one to do the job alone?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #116204 by </B><A HREF=/tutors/aboutme.mpl?userid=gonzo><B>gonzo(654)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=gonzo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=116204\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> not terribly sure because ran out of time but i think this is the answer.<BR>\n" );
document.write( "let p1 = rate of the larger pump.<BR>\n" );
document.write( "let p2 = rate of the smaller pump.<BR>\n" );
document.write( "both pumps working for 5 hours can drain the tank.<BR>\n" );
document.write( "so 5*p1 + 5*p2 = x where x is the amount of fuel in the tank.<BR>\n" );
document.write( "which means p1 is pumping for 5 hours and p2 is pumping for 5 hours.<BR>\n" );
document.write( "problem states that pump 1 can drain the tank by itself in 4 hours less than pump 2 can drain the tank by itself.<BR>\n" );
document.write( "so p1 * (t-4) = x<BR>\n" );
document.write( "and p2 * (t) = x<BR>\n" );
document.write( "if they both work by themselves than they both can drain 2 * the tank.<BR>\n" );
document.write( "so p1 * (t-4) + p2 * (t) = 2x = 10*p1 + 10*p2 since in 10 hours they can both drain the tank twice working together.<BR>\n" );
document.write( "so, .....<BR>\n" );
document.write( "p1 * (t-4) = 10 * p1<BR>\n" );
document.write( "and p2 * (t) = 10 * p2<BR>\n" );
document.write( "solving for p1 we get<BR>\n" );
document.write( "p1 * t - 4 * p1 = 10 * p1<BR>\n" );
document.write( "which becomes<BR>\n" );
document.write( "p1 * t = 6 * p1<BR>\n" );
document.write( "which becomes<BR>\n" );
document.write( "t = 6<BR>\n" );
document.write( "it takes p1 6 hours to drain the tank.<BR>\n" );
document.write( "solving for p2 we get<BR>\n" );
document.write( "p2 * t = 10 * p2<BR>\n" );
document.write( "which becomes\r<BR>\n" );
document.write( "\n" );
document.write( "t = 10<BR>\n" );
document.write( "it takes p2 10 hours to drain the tank.<BR>\n" );
document.write( "answer is it takes p2 10 hours to drain the tank.<BR>\n" );
document.write( "p1 takes 6 hours which is 4 hours less so the equation looks sound.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );