document.write( "Question 157620: A man is now 6 times as old as his son. In 6 yrs, the father will be 3 times as old as the son will be then. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #116190 by ptaylor(2198) You can put this solution on YOUR website! Let x=son's age now \n" ); document.write( "x+6=son's age 6 years from now \n" ); document.write( "Then 6x=father's now \n" ); document.write( "6x+6=fathers age in 6 years\r \n" ); document.write( "\n" ); document.write( "Now we are told that: \n" ); document.write( "6x+6=3(x+6) get rid of parens (distributive law) \n" ); document.write( "6x+6=3x+18 subtract 3x and also 6 from each side \n" ); document.write( "6x+6-6-3x=18-6+3x-3x collect like terms \n" ); document.write( "3x=12 \n" ); document.write( "x=4 years old -------------------present age of son \n" ); document.write( "6x=6*4=24 years old---------------present age of father\r \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( "24+6=3(4+6) \n" ); document.write( "30=30\r \n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor \n" ); document.write( " |